解:由1/x-1/y=1,变形两边各乘以xy,得,y-x=3xy,∴xy=1/3(y-x),(2x-14xy-2y)/(x-2xy-y)=[2x-14/3(y-x)-2y]/ [ x-2/3(y-x)-y) ],分式上下中此悄各乘以3,卖渣并展开括号,得3(2x-14/3y+14/3x-2y)/3(x-2/3y+2/3x-y)=(6x-14y+14x-6y)/(3x-2y+2x-3y)=(20x-20y)/(5x-5y)=4(5x-5y)/(5x-5y)=4 祝学习进步扒洞
相关文章
-
舜龙SL-12X91
2023-04-26 14:30 阅读(581) -
1X2X3X4X5X6X7X8X9……X100末尾有多少个0?
2023-04-14 04:11 阅读(560) -
已知关于x的一元二次方程x2-2x-a=0.
2023-03-29 14:36 阅读(562)